ESPECIAL CASES

by • 22/08/2013 • GeneralComments (0)468

ESPECIAL CASES

 

PROCESS AT CONSTANT VOLUME

INTRODUCTION:

In this process the volume of thermodynamic system is kept constant by using a container with fixed piston.

MATHEMATICAL FORM:

Since volume does not change

∆V = 0

Therefore

q = ∆E + P∆v

q = ∆E + P(0)

qv = ∆E

 

CONCLUSION:

According to eq (*) we can say that at constant volume the heat energy absorbed or released by system is utilized to change the internal energy of system.

PROCESS AT CONSTANT PRESSURE

 

INTRODUCTION:

In the process at constant pressure either a normal atmospheric pressure or a uniform pressure on the piston is maintained throughout.

MATHEMATICAL FORM:

As we know

q = ∆E + P∆y

q = E2- E1+ P(V2- \/1)

q = E2- E1+ PV2- PV1

q = (E2+PV2) – (E1 + PV1)

Let

H = E + PV

H1= E1+ PV1

H2 : E2 + PV2

 

So that,

q =  H2 – H1

qp = ∆H ——– (*)

 

CONCLUSION:

According to eq. (*) we can conclude that at constant pressure the total heat energy absorbed or released by system is utilized to change the enthalpy of the system.

The work of dickens and homework help thackeray, the inside estimate is the work
Pin It

Leave a Reply